python爬取：爬虫 -- 某一天基金网数据简易爬取

import requests
import time
import pandas as pd

if __name__ == '__main__':
    for j in range(1, 49):
        url = f'http://fund.eastmoney.com/Data/Fund_JJJZ_Data.aspx?t=1&lx=1&letter=&gsid=&text=&sort=zdf,desc&page={j},200&dt=1597126258333&atfc=&onlySale=0'
        headers = {
            'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.71 Safari/537.1 LBBROWSER'
        }
        resp = requests.get(url, headers=headers).text
        str_ = resp[102:]
        list1 = eval(str_.split(",count")[0])
        print(f'已经抓取第{j}页')
        print(f'本页抓取{len(list1)}条数据信息')
        num = []
        name = []
        today_price = []
        yesterday_price = []
        day_value = []
        day_value_rate = []
        subscription_status = []
        redemption_status = []
        service_charge = []

        for i in range(len(list1)):
          # 1	、基金代码号
            num.append(list1[i][0])
            # 2
、股票名称
            name.append(list1[i][1])
      # 3、今日股票基金净收益
            today_price.append(list1[i][3])
            # 4	、昨日股票基金净收益
            yesterday_price.append(list1[i][5])
            # 5、日提高值
            day_value.append(list1[i][7])
            # 6
、日年增长率
            day_value_rate.append(list1[i][8])
            # 7、认购情况
            subscription_status.append(list1[i][9])
            # 8	、赎出情况
            redemption_status.append(list1[i][10])
            # 9
、服务费
            service_charge.append(list1[i][17])

        df = pd.DataFrame()
        df['基金代码'] = num
        df['基金名称'] = name
        df['2020-08-12\n单位净值'] = today_price
        df['2020-08-11\n单位净值'] = yesterday_price
        df['日提高值'] = day_value
        df['日年增长率\n%'] = day_value_rate
        df['认购情况'] = subscription_status
        df['赎出情况'] = redemption_status
        df['服务费'] = service_charge

        try:
            df.to_excel(f'股票基金{j}.xlsx', '基金信息', index=None, encoding='utf-8')

        except Exception as e:
            print(e)

    time.sleep(1)